Find the length of the curve. 1² (2t+1)³/2 X= 2 3 The length of the curve is 1, y = 0≤t≤2 (Simplify your answer.)

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A: log3(2x23+y )+tan(xπ-πy)= sin-1(x2-1)+π21log(3). 2x23+y 23×23x-13+y'+sec2(xπ-πy).(πxπ-1-πy.…

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A: limx→1-log12(x+3)1-cosh(cos-1x)=limx→1- log2-1(x+3)1-cosh(cos-1x)since, limx→af(x). g(x)=limx→a f(x)…

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A: Let's find.

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