Find the limit or show that it doesn't exist. 1-х-х2 a) limx→-o 2х2-7 V1+4x6 b) limx 2-х3
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- Evaluate the limit limx→5 x^2 − 2x −15 / x−5 Enter I for ∞, −∞ and DNE if the limit does not exist.9. Find the value of a such that exists and find the limit. limx-> -1 (2x2-ax-14)/(x2 -2x-3)Find the limit or determine that the limit does not exist limx→∞ (2-x)/(√4x2 + 13) 4x2 + 13 is all under the square root
- Find the limit if it exists. lim(x,y) ---> (0,0) (x4-16y4)/(x2+4y2)Estimate the limit numerically if it exists. (If an answer does not exist, enter DNE.) lim x→+∞ 5x2 + 4x − 6 2x2 − 3xIf x4 <=ƒ(x)<= x2 for x in [-1, 1] and x2<=ƒ(x) <= x4 for x <-1 and x> 1, at what points c do you automatically know limx-->c ƒ(x)? What can you say about the value of the limit at these points?