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- Find the solution of the limit using polar coordinate system. Lim (x,y)->(0,0)√x^2+y^2/x^2+y^2Find the arclength of y = 2x3/2 on the interval x is greater than or equal to 1 and less than or equal to 2Use polar coordinates to find the limit. [Hint: Let x = r cos(?) and y = r sin(?), and note that (x, y) approaches (0, 0) implies r approaches 0.]lim as (x,y) -> (0,0) (xy^2)/[(x^2)+(y^2)].