Find the maximum and minimum values of the function f(x, y, z) = 3x – y – 3z subject to the constraints x2 + 2z? = 4 and x + y - z = 2. Maximum value is 12sqrt2-2 occuring at ( 2sqrt2 2-3sqrt2 -sqrt2 ). Minimum value is -2-12sqrt2 occuring at ( -2sqrt2 2+3sqrt2 sqrt2 ).

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