Find the mean and rms values of the waveform in the figure: 5 g(t) А 0 1 2 t(ms)
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- The voltage waveform during the first half cycle are from t = 0 to t = 0.01 increases linearly from 50 to 100 V and during the remaining half cycle from -50 to –100 V. Determine the rms value of the voltage.Determine the rms value for each of the waveforms below.1. A Sinusoidal current has an rms value of 5mA. Determine the following values. 1) Peak 2) Average 3) Peak to Peak
- (b) An engineer is required to analyse a sinusoidal waveform for the voltage and current using oscilloscope. The voltage waveform produced Root Mean Square (RMS) value at 75 V with positive-going zero crossing at 30°. While the RMS value of current is 66.71 A with negative-going zero crossing at 0.349 rad. Assume the frequeney of both waveforms is 50 Hz. (i) Sketch the voltage and current waveform in the same axis by showing the important point. (ii) Determine instantaneous voltage when t = 8ms . (iii) Determine phase relationship between voltage and current waveform.In an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 10 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is reduced to the half value? 3.536 Vrms . 3.536 Vrms O 5 Vrms . 1.7677 Vrms O 3.536 Vrms. 1.7677 Vrms O 5 Vrms . 5 Vrms ...... O 10 Vrms . 10 Vrms ......Q2. For the Periodic Waveforms shown in the Figure, determine for each : Frequency, Average Value over half a cycle, RMS Value, Form Factor, and Peak Factor. 100 75 Voltage (V 50 25 20 40 Time (ms) 10 30 -100