Find the minimum distance from the point (8, 3, 4) to the plane x - y + z = 4. (Hint: To simplify the computations, minimize the square of the distance.) Part 1 of 5 Let (x, y, z) be a point in the plane x – y + z = 4. Substituting z in terms of x and y, this point is given by (х, у, 2) %3D (х, у, 4 — || + y). =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 27E
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Find the minimum distance from the point (8, 3, 4) to the plane x - y + z = 4. (Hint: To simplify the
computations, minimize the square of the distance.)
Part 1 of 5
Let (x, y, z) be a point in the plane x - y + z = 4. Substituting z in terms of x and y, this point is given by
(х, у, 2) %3D (х, у, 4 -||
+ y).
Transcribed Image Text:Find the minimum distance from the point (8, 3, 4) to the plane x - y + z = 4. (Hint: To simplify the computations, minimize the square of the distance.) Part 1 of 5 Let (x, y, z) be a point in the plane x - y + z = 4. Substituting z in terms of x and y, this point is given by (х, у, 2) %3D (х, у, 4 -|| + y).
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