Find the minimum value of f(x, y, z) = x² + 2y² + 3z? subject to the constraint x + 2y + 3z = 10. Show that f %3D has no maximum value with this constraint.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 17EQ
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16. Find the minimum value of f(x, y, z) = x² + 2y² + 3z?
subject to the constraint x + 2y + 3z = 10. Show that f
has no maximum value with this constraint.
There is only one critical point, so the minimum value of the function occurs at
Enter your answer in the form:(
,7/5,2/9,1/3) with the parentheses, but no spaces.
Note: The fact that we don't have both a maximum and a minimum does not violate the Extreme Value Theorem because the constraint isn't bounded in R^3.
Transcribed Image Text:16. Find the minimum value of f(x, y, z) = x² + 2y² + 3z? subject to the constraint x + 2y + 3z = 10. Show that f has no maximum value with this constraint. There is only one critical point, so the minimum value of the function occurs at Enter your answer in the form:( ,7/5,2/9,1/3) with the parentheses, but no spaces. Note: The fact that we don't have both a maximum and a minimum does not violate the Extreme Value Theorem because the constraint isn't bounded in R^3.
Expert Solution
Step 1

Consider the given:

fx,y,z=x2+2y2+3z2Subject to constraints:x+2y+3z=10gx,y,z=x+2y+3z10

Use Lagrange’s Multipliers:

f=λgThis can be written as:fx=λgxfy=λgyfz=λgzFind the partial derivatives:fx=2xfy=4yfz=6zgx=1gy=2gz=3

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