Find the Normalized BW Delay Product Efficiency: 1-Two-Stations (show your work) (in terms of propagation time tprop, Transmission Bit Rate R and frame length L bits/frame) 2- Repeat above for the CSMA/CD (show your work) 3-Repeat above for the Token Ring (show your work)
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Find the Normalized BW Delay Product Efficiency:
1-Two-Stations (show your work) (in terms of propagation time tprop, Transmission Bit Rate R and frame length L bits/frame)
2- Repeat above for the CSMA/CD (show your work)
3-Repeat above for the Token Ring (show your work)
Step by step
Solved in 2 steps with 9 images
- Two channels one with a bit rate of 190Kbps and another with a bit rate of 180 Kbps are to be multiplexed with Pulse-Stuffing TDM with no synchronization bits. Answer the following questions. i) Calculate size of Frames in bits. ii) Calculate the Frame rate. iii) Calculate the duration of Frame.Two channels, one at 190Kbps and the other at 180Kbps, are to be multiplexed using Pulse-Stuffing TDM with no synchronisation bits. Please respond to the following questions. I Determine the size of frames in bits. ii) Determine the frame rate. iii) Determine the duration of Frame.Sketch the signal to carry through the medium if the sequence of bits to send using Differential Manchester line encoding scheme is 1110010110
- Sketch the signal to carry through the medium if the sequence of bits to send using AMI line encoding scheme is 1110010110Consider a 1Mbps transmission channel. The clock at the receiver has a drift of 1 second in one year. How long asequence of bits (or frame) can be sent before the clock drift could cause a problem? Assume that the sender and receiver are synchronized at the beginning of each frame and that they cannot resynchronize during the frame. Also, assume that the receiver samples the received signal at the middle of each bit duration to detect if it is 0 or 1.Match the given baud rate and the number of bits carried by each signal unit (baud rate, bits) with the bit rate. choose between : 1200 , 3600 , 3200 1200, 3 Answer 1 600, 6 Answer 2 1200, 1 Answer 3 600, 2 Answer 4 800, 4 Answer 5
- The data [0 1 0 0 0 1 0 1 1 1 0 0 1 1 1] is generated in an information signal with a speed of 64 kbit / s. This information mark [1 0 0 1 0 1] is transmitted using GPSK modulation with the spectrum code division multiple access (DSSS-CDMA) method, which is spread directly with the sequence, using the spreading sequence . 1- Show the bit sequence generated after spreading. 2- Show that the disseminated information can be retrieved at the receiver.For the following stream of digital signal which is being transmitted by bit rate 5 Kbps: 101100000000110 a) Draw the waveform for all line codes you studied. b) Determine if the line code is self synchronized or not. c) Determine if the code can be used with ac coupling or not d) Determine the Bandwidth of the line code e) Which code is used in magnetic recording f) Which code is used in LANA serial transmission T1 uses 8 information bits, 2 start bits, 1 stop bit and 1 parity bit for each character. A synchronous transmission T2 uses 3 eight-bit sync characters followed by 30 eight bit information characters. If the bit rate is 1200 bits/second in both cases, what are the transfer rates of T1 and T2?
- What is the main disadvantage of using FSK over ASK for digital communication? A. FSK is more prone to noise and interference. B. FSK is less power efficient. C. FSK requires more complex circuitry. D. FSK can only transmit data over a narrow range of frequencies.In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 2 kbps? How many if the data rate is 2 Mbps?We want to transmit 1000 characters with each character encoded as 8 bits. a. Find the number of transmitted bits for synchronous transmission. b. Find the number of transmitted bits for asynchronous transmission. c. Find the redundancy percent in each case.