Find the partial derivative of z with respect to x z = (3x² + 1) cos(x²y). əz = -2x (3x² + 1) sin(x²) + 6xcos (x²) da əz = -2xy (3x² + 1) sin(x²y) + 6xcos (x²y) da −2xy' (3x² + 1) sin(x²y) — 6xcos (x²y) -2x (3x² + 1) sin(x²y) + 6xcos (x²y) əz да da None of the choices 02 for əz da

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the partial derivative of z with respect to x
2 =
(3x² + 1) cos(x²y).
əz
=
-2x (3x² + 1) sin(x²) + 6xcos (x²)
da
əz
=
−2xy (3x² + 1) sin(x²y) + 6xcos (x²y)
da
= -2xy (3x² + 1) sin(x²y) - 6xcos (x²y)
da
-2x (3x² + 1) sin(x²y) + 6xcos (x²y)
da
O None of the choices
O
əz
D) for
Transcribed Image Text:Find the partial derivative of z with respect to x 2 = (3x² + 1) cos(x²y). əz = -2x (3x² + 1) sin(x²) + 6xcos (x²) da əz = −2xy (3x² + 1) sin(x²y) + 6xcos (x²y) da = -2xy (3x² + 1) sin(x²y) - 6xcos (x²y) da -2x (3x² + 1) sin(x²y) + 6xcos (x²y) da O None of the choices O əz D) for
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