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Find the perpendicular distance from the line given oy the parametric equations: by, (-3,3,3) a(t)= -2-7t to the point ylt)= 2 +4t %3D 2(E) = 3-10t %3D

Find the perpendicular distance from the line given oy the parametric equations: by, (-3,3,3) a(t)= -2-7t to the point ylt)= 2 +4t %3D 2(E) = 3-10t %3D

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.4: Plane Curves And Parametric Equations
Problem 34E
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Can someone help me figure out what I am doing wrong, please?? Thank you!
COS O = 3496029494 Cos (69.5369168359 7 Find the perpendicular distance from the line given oy the parametric equations: a(t)= -2-7t to the point ylt)= 2+4t 2(t) = 3- 10t (-3,3,3) Q= ((3,3,3) P=(-2,2,3) t =0 X6)= -2-7(0) = 63-2,3-2,3-3) (-5,,0) 2 + 4(0) = 2 Z 10) = P = <G3-2),(3-2),63-3)> K-5,1,07 component form 3-10 (0) 3 PLub INTO nd directhional vector <abic) Ei=<-7,4,-109 Pà = <+5,1,0). VE K-7,4,-10> Po xV = ((,-10)- (o 14), 10.-7)-(-5.-10),(-5-4)-(1.-7)> 0-50 -20 +7 K-101-50-13.7 loo + 2500 t 169 2769 41+16+100
Transcribed Image Text:COS O = 3496029494 Cos (69.5369168359 7 Find the perpendicular distance from the line given oy the parametric equations: a(t)= -2-7t to the point ylt)= 2+4t 2(t) = 3- 10t (-3,3,3) Q= ((3,3,3) P=(-2,2,3) t =0 X6)= -2-7(0) = 63-2,3-2,3-3) (-5,,0) 2 + 4(0) = 2 Z 10) = P = <G3-2),(3-2),63-3)> K-5,1,07 component form 3-10 (0) 3 PLub INTO nd directhional vector <abic) Ei=<-7,4,-109 Pà = <+5,1,0). VE K-7,4,-10> Po xV = ((,-10)- (o 14), 10.-7)-(-5.-10),(-5-4)-(1.-7)> 0-50 -20 +7 K-101-50-13.7 loo + 2500 t 169 2769 41+16+100
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