Find the points at which the graph of the equation has a vertical or horizontal tangent line. 16x2 + y2 32x + 8y + 16 = 0 (x, y) = horizontal tangents vertical tangents (x, y) = (x, y) = =([ (x, y) = (smaller y-value) (larger y-value) (smaller x-value) (larger x-value)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 25E
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Find the points at which the graph of the equation has a vertical or horizontal tangent line.
16x² + y² - 32x + 8y + 16 = 0
(x, y) =
horizontal tangents
vertical tangents
(x, y) =
(x, y) =
(x, y) =
(smaller y-value)
(larger y-value)
(smaller x-value)
) (larger x-value)
Transcribed Image Text:Find the points at which the graph of the equation has a vertical or horizontal tangent line. 16x² + y² - 32x + 8y + 16 = 0 (x, y) = horizontal tangents vertical tangents (x, y) = (x, y) = (x, y) = (smaller y-value) (larger y-value) (smaller x-value) ) (larger x-value)
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