Find the points at which the graph of the equation has a vertical or horizontal tangent line. 36x2 + 16y2 + 288x - 192y + 576 - 0 horizontal tangents (x, y) = 4.0 (smaller y-value) (x, y) = (-4,2 (larger y-value) vertical tangents (х, у) %3D -8,6 (smaller x-value) C06 (larger Yalvalue)

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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Find the points at which the graph of the equation has a vertical or horizontal tangent line.
36x2 + 16y2 + 288x – 192y + 576 = 0
horizontal tangents
(x, y) = ( 4,0
(smaller y-value)
(х, у) 3 (| —4,2
(larger y-value)
vertical tangents
(х, у) %3D
(-8,6
(smaller x-value)
(x, y) = (| 0,6
(larger x-value)
Transcribed Image Text:Find the points at which the graph of the equation has a vertical or horizontal tangent line. 36x2 + 16y2 + 288x – 192y + 576 = 0 horizontal tangents (x, y) = ( 4,0 (smaller y-value) (х, у) 3 (| —4,2 (larger y-value) vertical tangents (х, у) %3D (-8,6 (smaller x-value) (x, y) = (| 0,6 (larger x-value)
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