Find the points on the lemniscate where the tangent is horizontal. 2(x² + y?)² = 25(x? – y?) (х, у) (smaller x-value, smaller y-value) (х, у) %3 (smaller x-value, larger y-value) (х, у) %3 (larger x-value, smaller y-value) (х, у) 3D (larger x-value, larger y-value) y

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter6: Rates Of Change
Section6.1: Velocity
Problem 12SBE
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Find the points on the lemniscate where the tangent is horizontal.
2(x2 + y2)2 = 25(x² – y²)
(х, у)
(smaller x-value, smaller y-value)
(х, у) %3D
(smaller x-value, larger y-value)
(х, у)
(larger x-value, smaller y-value)
(х, у) 3D (
(larger x-value, larger y-value)
yA
Transcribed Image Text:Find the points on the lemniscate where the tangent is horizontal. 2(x2 + y2)2 = 25(x² – y²) (х, у) (smaller x-value, smaller y-value) (х, у) %3D (smaller x-value, larger y-value) (х, у) (larger x-value, smaller y-value) (х, у) 3D ( (larger x-value, larger y-value) yA
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