Find the position vector R(t) given the velocity V(t) = (10t + 3) i+ 15 sin(3t) j+ 20t° k and the initial position vector R(0) = -31 – 3j – 3k. R(t) =
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- find the velocity and acceleration vectors in terms ofur and uθ . r = a(1 + sin t) and θ = 1 - e-tA particle is moving with velocity V(t) = ( pi cos (pi t), 3t2+ 1) m/s for 0 ≤ t ≤ 10 seconds. Given that the position of the particle at time t = 2s is r(2) = (3, -2), the position vector of the particle at t is?How do you find the velocity and acceleration vectors at t=-1?
- The equation for the position vector r(t) of the particle at time t isFind the position vector for the particle with acceleration, initial velocity, and initial postion given below. a(t)= <5t,3sin(t), cos(3t) v(0)= <3,0,-2>r(0)= <0,5,-2>r(t)=?Find the position vector for a particle with acceleration, initial velocity, and initial position given below a(t)= r(0)= r(t)=?
- give the position vectors of particles moving alongvarious curves in the xy-plane. In each case, find the particle’s velocityand acceleration vectors at the stated times, and sketch them asvectors on the curve. Motion on the parabola y = x2 + 1r(t) = ti + (t2 + 1)j; t = -1, 0, and 1The angle between the velocity and acceleration vectors at time t=0 isCalculate the velocity and acceleration vectors and the speed at the time indicated.r(θ) =〈sin θ, cos θ, cos 3θ〉, θ = π/3
- The velocity of a particle is given in terms of the time t by v = sinti - 2cos(2t)j + t2k where i, j and k are the Cartesian unit vectors. What is the acceleration of the particle when t = π ?Use the given acceleration vector and initial conditions to find the velocity and position vectors. Then find the position at time t = 2.Determine the rate of change of the function g(x, y) = y2 tan(x − 2y + 4) at the point (π /4 , 2) in the direction of the vector v = 2i − 2j.