Find the position vector R(t) given the velocity V(t) = (4t + 3) i + 6 sin(3t) j+ 6r² k and the initial position vector R(0) = -31+ 3/+ k. R(t) =
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- find the velocity and acceleration vectors in terms ofur and uθ . r = a(1 + sin t) and θ = 1 - e-tA particle is moving with velocity V(t) = ( pi cos (pi t), 3t2+ 1) m/s for 0 ≤ t ≤ 10 seconds. Given that the position of the particle at time t = 2s is r(2) = (3, -2), the position vector of the particle at t is?How do you find the velocity and acceleration vectors at t=-1?
- Find the position vector for the particle with acceleration, initial velocity, and initial postion given below. a(t)= <5t,3sin(t), cos(3t) v(0)= <3,0,-2>r(0)= <0,5,-2>r(t)=?Find the derivative of the vector functionr(t)=ta×(b+tc), wherea=⟨3,−2,−3⟩, b=⟨1,3,−2⟩, and c=⟨−2,−4,−4⟩.r′(t)=⟨ , , ⟩Find the 2-dimensional position vector R(t) given the velocity V(t) = cos(ti) + t^3j and the initial position R(0) = i − 2j.
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