Find the slope of the secant line which connects the points (-2, 4) and (2, 0) on the following curve. Next, using the Mean Value Theorem, just find the x-value at which the line tangent to f(x) is parallel to this secant line. fx) = - -x + 6 y (-2, 4), 4 2 (2, 0) -4 2 O a. 1 O b. y = - 2x - 1 O C.x = 0

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A: Given,         y=x3-3x2-9x+12

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A: Rule:-equation of line passing thraught (x1,y1) and (x2,y2) is y-y1=y2-y1x2-x1(x-x1)

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A: Slope of the tangent =rate of change  According to the graph

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A: Please see the answer below.

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