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A: Given,
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A: Explanation of the answer is as follows
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A: We have to find
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Q: (a) Find the point at y = x³ + x, if the slope is equal to 4. Then find the equation of tangent…
A: Slope is derivative of y with respect to x. And equation of tangent is (y-y1) =m(x-x1).
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Q: For what x-values that the curve ?(?) = (1/3)x3-x2 have horizontal tangent lines?
A: fx=13x3-x2 Differentiating with respect to x, we get f'x=133x2-2x ∵dxndx=nxn-1=x2-2x
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A: In this question , we can find the value of the slope of the given curve . Differentiate the given…
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A: Since you have asked multiple questions, we will solve the first question (i.e., Question-8) for…
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Q: The slope of the tangent line to the curve y = x² + 4x + 7 at x = 1 is Blank 1. Blank 1 Add your…
A: The solution of the problem is given in the next step.
Q: What is the value of the slope of the tangent line to the curve x2- 2xy – 2y²=1 passing through the…
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Q: Find the slope of the tangent line to the curve 4x2 – 3xy + 2y = – 16 at the point (4, – 4). Add…
A: Given : 4x2−3xy+2y3=−16 (x,y)=(4,−4)
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Q: What is the value of the slope of the tangent line to the curve x2- 2xy – 2y² = 1 passing through…
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Q: help pls and thanks. find the equation of the line tangent to. f(x)= (2x^2-x)/x at point (1,3)
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A: y= x+1 / x-7 (6,-7 ) x- y - =13
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Q: Question 6
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Q: What is the value of the slope of the tangent line to the curve x2+4xy+y²=13 passing through the…
A: As we know that; The slope of the tangent line to the given curve is equal to the first derivative…
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- Find the tangent and normal line to the curve at the specified condition. 3x3 - x2 - 12x + 6 at the points where the curve crosses the line y = 2Find the points on the curve y=2x^3 + 3x^2 -12x +3 where the tangent line is horizontal. (x,y) = ( , ) (smaller x-value) (x,y) = ( , ) (larger x-value)Find The Slope Of The Tangent Line (16 - X)Y^2 = X^3 At The Point (8, 8)
- find tangent line to the curve y=3x/7-x at a point of (-3,2/7)Find the slope of the tangent line to the curve y= square root x^2 - 9 at the point P(5,4) by using a difference quotient. Show your work.Find equations of the tangent line and normal line tothe curve at the given point. y= 6Cosx (π/3, 3)
- Find the points on the curve y = 2x3 + 3x2 − 12x + 5 where the tangent line is horizontal. (x, y) = (smaller x-value) (x, y) = (larger x-value)Find the points on the curve y = 2x3 + 3x2 − 12x + 3 where the tangent line is horizontal.Find the slope of the tangent line drawn to the graph of −4x^2−xy+3y^3=−200 at the point (−1,−4). Enter exact values.
- Find the points on the curve y = 2x3 - 3x2 - 12x + 20 where the tangent line is a. perpendicular to the line y = 1 - (x/24). b. parallel to the line y = sqrt(2) - 12x.What is the tangent line to y= 1/2arctan(1/5x) at the point (5,π/8)?Find the slope of the tangent line drawn to the graph of 2x2−xy−y3=5 at the point (2,1). Enter exact values. slope: m=