Question

Asked Oct 7, 2019

Find the slope of the tangent line to the curve defined by

6x^{5 }+ 8xy +y^{2 }= -13 at (-1,1).

The slope of the curve at the point (-1,1) is ?

Step 1

The slope of tangent line to the curve f(x,y)=0 at (a,b) is the value of dy/dx at (a,b)

Step 2

We differentiate both sides of given equation of curve to find dy/dx

Step 3

Then we substitute x=-1 and y=1 in dy/dx to get the value o...

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