Find the slope of the tangent line to the curve defined by
6x5 + 8xy +y2 = -13 at (-1,1).
The slope of the curve at the point (-1,1) is ?
The slope of tangent line to the curve f(x,y)=0 at (a,b) is the value of dy/dx at (a,b)
We differentiate both sides of given equation of curve to find dy/dx
Then we substitute x=-1 and y=1 in dy/dx to get the value o...
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