Find the smallest positive solution x: (sec(x)+3)(sec(x)+5) = 4 Assume radians.

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A: Given :                    sec x + tan x = 1               in the interval [0,2pi) To find :…

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A: basic formulae required to solve the above question: cos2x=1-2sin2x function positive in…

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A: Known fact: sinA+B=sinA cosB+cosA sinB

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A: Explanation of the answer is as follows

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A: trignometric expression

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A: sec x=1+tan x⇒sec x-tan x=1   (1) sec2x- tan2x=1    (2)Divide (2) by (1)sec x+tan x=1     (3)Add (1)…

Q: i) Find sin 6x+ cos 4x dx. 3 ii) Evaluate || et -dx . Hence, solve 2e* dx . (* +2)" +2

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A: Given, function is

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A: Given, sin 2x + sin x = 0 We know, sin 2x = 2sin x.cos x   2sin x.cos x + sin x = 0. sin x(2cos x +…

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A: To solve the given equation

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Q: Solve the equation for exact solutions over the interval [0, 2π). sin 2x + sin x = 0

A: The given equation is- sin2x+sinx=0 Solving the equation to find sinx- sinxsinx+1=0sinx=0,-1

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Q: Determine exact solutions for each equation on the interval 0 ≤ x ≤ 2π. a) Cost | +²1=0 b) sin3x = 0…

A: We can answer both the question as below.

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A: NOTE: Refresh your page if you can't see any equations. . use the formula

Q: solve the equation on [0,2pi) sec^2 x + tan x = 1

A: Given:sec^2 x + tan x = 1

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Q: Solve the equation graphically on the interval (0, 2π] tan(x)+5sin(x)=2

A: Given equation is tanx+5sinx=2. Need to solve the equation graphically.

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A: Given  [ 0

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A: we use   cos(2x) = 1 - 2sin2x   The equation becomes 1 - 2sin2x - sinx = 1 2sin2x + sinx = 1…

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A: There are exponential function and trigonometric functions in the product in the given integrand.…

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Q: Solve the equation for exact solutions over the interval [0, 2π). sin2x + sin x = 0

A: Trigonometry Question

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A: Equation given in the question is: We can solve each part separately as follows:

Q: Find the exact value. 11n sin 12 V6 - V2 A) B) V3- 2 4 -V6 - V2 C) V2 - V6 D) 4 4-

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Q: Solve the equation on the interval [0, 2r). sin2 x - cos? x = 0

A: We need to solve the equation-   sin2x-cos2x=0    in interval [0,2π) Here we will use the following…

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A: Solution is given below: