Find the solution for the potential in a dielectric region for which er=3, the potential ? is 30 V at p=4 and V=60 V at p=2 V=-43.3 In p+50 O V= 67.2 In p-80 O V= 13.2 In p+24 O none
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- A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?A parallel-plate capacitor using a dielectric material having an Pr of 2.2 has a plate spacing of 2 mm (0.08 in.). If another material having a dielectric constant of 3.7 is used and the capacitance is to be unchanged, what must the new spacing be between the plates?A silicon wafer is doped n=1.0*10^16cm^-3 with Boron .Find answers for temperature T=0K and T=300K respectively.(1) Is this substance a conductor, an insulator or a semiconductor?If it is a conductor, is it P or N?(2) What is the concentration of electrons and holes?(3)Where is the location of Fermi energy? How far is it from the valence band? Draw an energy band diagram.
- Figure 2 shows a plot of electrical potential versus position along thex-axis.Make a plot of thex-component of the electric field for this situation.(imaged attached below)Solar panels on one of the NWU solar car prototype, have an emissivity of e = 0.655. When in direct sunlight, they absorb energy at a rate of 796 J/s per square meter of surface. Assume that the only energy loss is due to the emission of radiation. What equilibrium temperature are the panels reaching?Air breaks down and conducts charge as a spark if the electric field magnitude exceeds 3.00×106??3.00×106Vm. (a) Determine the maximum charge ?maxQmax that can be stored on an air-filled parallel-plate capacitor with a plate area of 2.00×104?22.00×104m2. (b) A 75.0??75.0μF air-filled parallel-plate capacitor stores charge ?maxQmax. Find the potential difference across its plates.
- At point P(-4, 3,6), if the potential field V=2x^2y – 5z, the magnitude of the electric field intensity is equal toBased on the band diagram, explain the difference in conductivity behavior between insulating materials and semiconducting materials as a function of temperature. Based on this answer, propose an explanation for the use of semiconductors such as GaN in high-power transmitters for wireless communication systems.A capacitor is made from two flat parallel plates placed 2 mm apart, .and its capacitance at vacuum is 10-12- F , if 200 volt applied in between then a Dielectric material was entered and its Dielectric constant Is 49 , Calculate : a) the new value of capacitance after the entrance of the Dielectric b) what is the value of charge on Dielectric material surface c) the polarization p of the Dielectric material d) calculate the displacement and the field inside the Dielectric
- When an ac potential of 1000 V is applied at a frequency of 1 MHz, a parallel-plate capacitor with dimensions of 38 mm by 65 mm and a plate spacing of 1.3 mm must have a minimum capacitance of 70 pF. Which of the materials listed in Table 2 might be a good fit? Why?Example/ Fermi Deric probability of le:vel above of Fermi level by 0.3 ev is 1% find Temperature in Degree.Find the boundary conditions required by the electric potential at the interface between two perfect dielectrics with dielectric constant εr1 and εr2.