Find the solution using Variation of parameter. Find the solution using Variation of parameter.(D2 – 1)y= ex +1y= Ce* + Cze¯*+ xe* – -ex – 141°y= C,e* + C2e¬*+ xe* - e* - 11ex - 1|21yy= C e* + Cze¬*=xe*-e*1ex – 141y= Cqe* + C2e¬2x.1+ =xe“ – ÷e* - 1

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Find the solution using Variation of parameter. (D2 – 1)y= ex +1 'y=Gje"+ Cae"* + 글 xe"-e-1 ex – 1 4 xex. 1 °y= C,e* + C2e¬*+ xe* - e* - 1 1 ex - 1 | 2 y= C e* + Cze¬*=xe*-e* ex – 1 4 1 y= Cqe* + C2e¬2x. 1 + =xe“ – ÷e* - 1

Find the solution using Variation of parameter. (D2 – 1)y= ex +1 'y=Gje"+ Cae"* + 글 xe"-e-1 ex – 1 4 xex. 1 °y= C,e* + C2e¬+ xe - e* - 1 1 ex - 1 | 2 y= C e* + Cze¬=xe-e* ex – 1 4 1 y= Cqe* + C2e¬2x. 1 + =xe“ – ÷e* - 1

Intermediate Algebra

10th Edition

ISBN:9781285195728

Author:Jerome E. Kaufmann, Karen L. Schwitters

Publisher:Jerome E. Kaufmann, Karen L. Schwitters

Chapter8: Conic Sections

Section8.2: More Parabolas And Some Circles

Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...

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