Find the solution. (D5 - 2D3 - 2D2- 3D - 2)y = 0. -3x y = (c,+c,x)e-*+c;e-+e*(c,cosx+c gsinxr) -2x A y = (c,+c,x)e-+ cze *+e=2*(c ,cosx +c ,sinx) B y = (c,+c,t)e*+cze +c,cosx + c gsinx y = c,e* +c,e*+c;e?"+c,cosr + c 3sinx D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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Question 15
Find the solution.
(D5 - 2D3 - 2D2- 3D - 2)y = 0.
-2x
A y = (c,+cx)e¯*+c,e=+e*(c,cosr +C gsinx)
® y = (c,+cx)e=«+c;e+e=(c,cosx + € zsinx)
-2x
y = (c,+c,x)e¯*+cze"+c_cosx+ c sinx
Dy = c,e*+c,e*+c;e* +c ,cosx +c zsinx
Transcribed Image Text:Question 15 Find the solution. (D5 - 2D3 - 2D2- 3D - 2)y = 0. -2x A y = (c,+cx)e¯*+c,e=+e*(c,cosr +C gsinx) ® y = (c,+cx)e=«+c;e+e=(c,cosx + € zsinx) -2x y = (c,+c,x)e¯*+cze"+c_cosx+ c sinx Dy = c,e*+c,e*+c;e* +c ,cosx +c zsinx
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