Find the sum of each series in Exercises 45–52. 4 6. 45. У 46. 2 3)(4n + 1) (4n (2n – 1)(2n + 1) n=1 40n 2n + 1 47. E | (2n 48. n'(n + 1)² 1)°(2n + 1)2 =D1 n=1 1 50. E n=1 \2/n 49. E Vn Vn + 1. 21/(n+1), n=1 1 51. У In (n + 2) In (n + 1), n=1 52. E(tan-(n) – tan¬1(n + 1)) n=1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
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Question
Find the sum of each series in Exercises 45–52.
4
6.
45. У
46. 2
3)(4n + 1)
(4n
(2n – 1)(2n + 1)
n=1
40n
2n + 1
47. E
| (2n
48.
n'(n + 1)²
1)°(2n + 1)2
=D1
n=1
1
50. E
n=1 \2/n
49. E
Vn
Vn + 1.
21/(n+1),
n=1
1
51. У
In (n + 2)
In (n + 1),
n=1
52. E(tan-(n) – tan¬1(n + 1))
n=1
Transcribed Image Text:Find the sum of each series in Exercises 45–52. 4 6. 45. У 46. 2 3)(4n + 1) (4n (2n – 1)(2n + 1) n=1 40n 2n + 1 47. E | (2n 48. n'(n + 1)² 1)°(2n + 1)2 =D1 n=1 1 50. E n=1 \2/n 49. E Vn Vn + 1. 21/(n+1), n=1 1 51. У In (n + 2) In (n + 1), n=1 52. E(tan-(n) – tan¬1(n + 1)) n=1
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