Find the tangential component aT of the acceleration vector of a particle moving in the plane with position function r(t) (18t – 6t*) i+ 18t² j. 1. aT 18t 2. ат — 36t 3. ат — —36t 4. aT = 18 – 18t2 5. ат -36t + 36
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- find the velocity and acceleration vectors in terms ofur and uθ .1. r =θ and dθ/dt = 2find the velocity and acceleration vectors in terms ofur and uθ . r = a(1 - cos θ) and dθ/dt = 3give the position vectors of particles moving alongvarious curves in the xy-plane. In each case, find the particle’s velocityand acceleration vectors at the stated times, and sketch them asvectors on the curve. Motion on the parabola y = x2 + 1r(t) = ti + (t2 + 1)j; t = -1, 0, and 1