Find the Taylor polynomials of orders n = 0,1,2,3 , and 4 about x = xo, and then find the nth Taylor polynomials, p. (x) for the function in sigma notation for f(x) = e; x0 = In7 Choose the correct answer. O po(x) = 7", P1(x) = 7"[1 + a(x + In7)]. p2(x) = 7" 1+ a(x+ In7) + a(x + In7)² 2! ax+ In7) a°(x+ In7)³ p3(x) = 7° 1+ a(x + In7) + 2! 3! a(x + In7) a'(x+ In7) a*x+ In7) P4(x) = 7° 1 + a(x+ In7) + 2! 3! 4! "a(x+ In7)* Pn (x) = k! O po(x) = 7", dx«- In7)²| P1(x) = 7"[1 + a(x – In7)], p2(x) = 7" | 1+ a(t – In7) + 2! a (x- In7) a?(x – In7)*| 3! P3(x) = 7" |1 + a(x- In7) + 2! a (x - In7) a²(x– In7) a*(x – In7)* P4(x) = 7° |1 + a(x – In7) + 2! 3! 4! 7°d(x- In7) Pa(x) = k!
Find the Taylor polynomials of orders n = 0,1,2,3 , and 4 about x = xo, and then find the nth Taylor polynomials, p. (x) for the function in sigma notation for f(x) = e; x0 = In7 Choose the correct answer. O po(x) = 7", P1(x) = 7"[1 + a(x + In7)]. p2(x) = 7" 1+ a(x+ In7) + a(x + In7)² 2! ax+ In7) a°(x+ In7)³ p3(x) = 7° 1+ a(x + In7) + 2! 3! a(x + In7) a'(x+ In7) a*x+ In7) P4(x) = 7° 1 + a(x+ In7) + 2! 3! 4! "a(x+ In7)* Pn (x) = k! O po(x) = 7", dx«- In7)²| P1(x) = 7"[1 + a(x – In7)], p2(x) = 7" | 1+ a(t – In7) + 2! a (x- In7) a?(x – In7)*| 3! P3(x) = 7" |1 + a(x- In7) + 2! a (x - In7) a²(x– In7) a*(x – In7)* P4(x) = 7° |1 + a(x – In7) + 2! 3! 4! 7°d(x- In7) Pa(x) = k!
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.3: Change Of Basis
Problem 17EQ
Related questions
Question
![O po(x) = a",
Pi(x) = a'[1 + a(r – In7)|. p2(x) = a
a (x- In7)*
+ a(x – In7) +
2!
a*(x – In7)² a'(x – In7)|
p3(x) = a' 1+ a(x- In7) +
+
2!
3!
a(x- In7) a'(x – In7) a (x- In7)*
4!
P4(x) =
= a'
+ a(x- In7) +
+1
2!
3!
a*+7(x- In7)*
Pa(x) = 2
k!
O po(x) = 1,
a cx- In7)
P1(x) = 1+ a(x In7), p2(x) = 1 + a(x – In7) +
2!
a (x- In7) a'c – In7)
P3(x) = 1+ a((x-In7) +
+.
2!
3!
a(x- In7) a (x – In7)*
a (x- In7)
P4(x) = 1+ a(x - In7) +
+.
2!
3!
4!
a'(x-In7)*
Pn(x) = >
k!
k=D0
O po(x) = 7",
P1(x) = 7" [1+ ax], p2(x) = 7" 1+ ax-
2!
a a
P3(x) = 7" 1 + ax +
2!
3!
ax
a'x
+.
2!
P4(x) = 7" 1 + ax +
3!
4.
7" ax
Pn(x) =
k!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4616885f-d6fc-4145-be16-5fc48622ffc5%2F74fae532-5eb9-409e-8913-7a1ab07948a0%2Fywprbww_processed.jpeg&w=3840&q=75)
Transcribed Image Text:O po(x) = a",
Pi(x) = a'[1 + a(r – In7)|. p2(x) = a
a (x- In7)*
+ a(x – In7) +
2!
a*(x – In7)² a'(x – In7)|
p3(x) = a' 1+ a(x- In7) +
+
2!
3!
a(x- In7) a'(x – In7) a (x- In7)*
4!
P4(x) =
= a'
+ a(x- In7) +
+1
2!
3!
a*+7(x- In7)*
Pa(x) = 2
k!
O po(x) = 1,
a cx- In7)
P1(x) = 1+ a(x In7), p2(x) = 1 + a(x – In7) +
2!
a (x- In7) a'c – In7)
P3(x) = 1+ a((x-In7) +
+.
2!
3!
a(x- In7) a (x – In7)*
a (x- In7)
P4(x) = 1+ a(x - In7) +
+.
2!
3!
4!
a'(x-In7)*
Pn(x) = >
k!
k=D0
O po(x) = 7",
P1(x) = 7" [1+ ax], p2(x) = 7" 1+ ax-
2!
a a
P3(x) = 7" 1 + ax +
2!
3!
ax
a'x
+.
2!
P4(x) = 7" 1 + ax +
3!
4.
7" ax
Pn(x) =
k!
![Find the Taylor polynomials of orders n = 0,1,2,3, and 4 about x = Xo, and then find the nth Taylor polynomials, p.(x) for the
function in sigma notation for
f(x) = e"; xo = In7
Choose the correct answer.
O po(x) = 7",
P1(x) = 7"[1 + a(x + In7)]. p2 (x) = 7" | 1+ a(x + In7) +
ax + In7)²
21
x+ In7) a°(x + In7)
P3(x) = 7°|1 + a(x + In7) +
2!
3!
P4 (x) = 7" | 1 + a(x + In7) +
a(x + In7) a°x+In7)
a*(x + In7)
2!
3!
41
7° af(x + In7)
Σ
Pn (x) =
k!
k0
O po(x) = 7",
a(x – In7)
P1(x) = 7"[1 + a(x – In7)], p2(x) = 7" | 1+ a(x – In7) +
2!
a (x– In7) a(x– In7)'
3!
P3 (x) = 7" 1 + a(x - In7) +
2!
P4(x) = 7" 1 + a(x – In7) +
a (x - In7) a?(x– In7)
a(x – In7)*
+
2!
3!
4!
7"a (x – In7yk
P.(x) =
k!
k=0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4616885f-d6fc-4145-be16-5fc48622ffc5%2F74fae532-5eb9-409e-8913-7a1ab07948a0%2Flc5sie_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the Taylor polynomials of orders n = 0,1,2,3, and 4 about x = Xo, and then find the nth Taylor polynomials, p.(x) for the
function in sigma notation for
f(x) = e"; xo = In7
Choose the correct answer.
O po(x) = 7",
P1(x) = 7"[1 + a(x + In7)]. p2 (x) = 7" | 1+ a(x + In7) +
ax + In7)²
21
x+ In7) a°(x + In7)
P3(x) = 7°|1 + a(x + In7) +
2!
3!
P4 (x) = 7" | 1 + a(x + In7) +
a(x + In7) a°x+In7)
a*(x + In7)
2!
3!
41
7° af(x + In7)
Σ
Pn (x) =
k!
k0
O po(x) = 7",
a(x – In7)
P1(x) = 7"[1 + a(x – In7)], p2(x) = 7" | 1+ a(x – In7) +
2!
a (x– In7) a(x– In7)'
3!
P3 (x) = 7" 1 + a(x - In7) +
2!
P4(x) = 7" 1 + a(x – In7) +
a (x - In7) a?(x– In7)
a(x – In7)*
+
2!
3!
4!
7"a (x – In7yk
P.(x) =
k!
k=0
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