Find the third term of: (z+3)2n Σ-0(-1)"+1 (2n)! O [(z-3)^8]/40320 O [(z-3)^2]/2 O [(z-3)^4]/24 O [(z-3)^6]/720

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter9: Sequences, Probability And Counting Theory
Section: Chapter Questions
Problem 46RE: Find the fourth term of (3a22b)11 without fully expanding the binomial.
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Find the third term of:
2n=n+1 (z+3)2n
(2n)!
(-1)"
n%3D0
[(z-3)^8]/40320
O [(z-3)^2]/2
O [(z-3)^4]/24
O
[(z-3)*6]/720
Transcribed Image Text:Find the third term of: 2n=n+1 (z+3)2n (2n)! (-1)" n%3D0 [(z-3)^8]/40320 O [(z-3)^2]/2 O [(z-3)^4]/24 O [(z-3)*6]/720
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