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Find the two x-intercepts of the function f and show that f '(x) = 0 at some point between the two x-intercepts. f(x)=x²-3x - 18 (x, y) = (-3,0 (x, y) = (6,0 ) (smaller x-value) ) (larger x-value) Find a value of x such that f '(x) = 0. x = 32 x

Find the two x-intercepts of the function f and show that f '(x) = 0 at some point between the two x-intercepts. f(x)=x²-3x - 18 (x, y) = (-3,0 (x, y) = (6,0 ) (smaller x-value) ) (larger x-value) Find a value of x such that f '(x) = 0. x = 32 x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the two x-intercepts of the function f and show that f '(x) = 0 at some point between the two x-intercepts. f(x)=x²-3x - 18 (x, y) = (-3,0 (x, y) = (6,0 ) (smaller x-value) ) (larger x-value) Find a value of x such that f '(x) = 0. X = 32 x
Transcribed Image Text:Find the two x-intercepts of the function f and show that f '(x) = 0 at some point between the two x-intercepts. f(x)=x²-3x - 18 (x, y) = (-3,0 (x, y) = (6,0 ) (smaller x-value) ) (larger x-value) Find a value of x such that f '(x) = 0. X = 32 x
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