Find the value of the integral x²dx (x² + 9)(x² + 4)² 0-

Q: Find the integral ∫(3x+2)5dx.

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Q: Find the integral of (2x+4)/(x^4+4)

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Q: 3x+1 2-2x+2

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Q: 3. Evaluate the integral x³ - 2x? – 4 dr x³ – 2x? |

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Q: 7x² dx Vx² – 16 - +C

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Q: x-3(x-1 + x)²dx

A: Given, ∫x-3x-1+x2dx It is required to evaluate the integral.

Q: x*- 2x³+x² xdx

A: ∫x4-2x3+x2xdx ∫x2x2-2x+1dx ∫x2(x-1)2dx ∫x2(x-1)dx ∫ x3 -x2dx x4/4 -x3/3 +c

Q: -25 Evaluate the integral: dax x²Vx2 +25

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Q: Solve the integral. r5 x° + 3 1. x2(x² + 2x + 1)

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Q: 6dx x - √ S 3√x²

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Q: Sæ² 1 + x²dx

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Q: Vx2 – 4 dr lx x3

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Q: x²dx V9-x2

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Q: 2 √₁² √√x² - 4x + 8

A: The solution is given in the next step.

Q: x+4 Calculate the integral 7x+6x-x2

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Q: Evaluate the integral. 6 1 (x² - 1)3/2 2 (x²

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Q: Evaluate the integral f2*-9x-9 dx x3-9x

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Q: Evaluate the integral ſ 2x²Vx³ + 2. Show all steps.

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Q: x2-6x+13

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Q: Find the integral ∫3√1−3xdx.

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Q: Evaluate the integral f(16x3 + 4x³)dx

A: To evaluate the integral: ∫16x3+4x3dx Use the formula: ∫xndx=xn+1n+1+C, where n≠1

Q: Evaluate the integral ∫ xdx / x2+2x+2.

A: On simplification, we get

Q: Evaluate the integral. r1/3 -1 2x = xp J1/7

A: ∫1713-12xdx=∫1713-12.1xdxWe know that ∫1x dx=ln(x)+cSo, ∫1713-12xdx=∫1713-12.1xdx

Q: 1 .2 VX /x²+2x +3

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Q: 5dx 3. S- V4e2x-36

A: Here we have to evaluate the integral:- I=∫5dx4e2x-36

Q: The integral 15x* - x* - 43x – 19 (x + 1)2(x2 – 6x + 13) can be rewritten as

A:

Q: b) Show that 2x² + 8x + 14 = 2 (x + 2)° +3 by completing the square. Hence, evaluate the integral-…

A: Use integration rules

Q: c) : Evaluate the integral xp- x2-4x-5

A: Given ∫xx2-4x-5dx

Q: evaluate the integral of " [(x^2)+1] / [(3x+1)^0.5] "

A: The given integral,        ∫x2+13x+1dx

Q: 2 x'-2x+1 xp: 4x3

A:

Q: Solve the integral. x4 – 2x3 + 2x² – 6x – 9 3. x(x² + 3)2

A: ∫x4-2x3+2x2-6x-9xx2+32dx Now partial fraction  =∫2x-2x2+3+2xx2+32-1xdx Apply linearity…

Q: Find the integral of f(3x2 + 4x + 1)*(3x + 2)

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Q: dx 9х2 — 12х — 5 9x2

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Q: Evaluate the integral [5x/( x²+1)(2x-2).

A: Given, the integral

Q: Evaluate the integral

A: ∫xndx=xn+1n+1+C

Q: x²dx 5 + + x2

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Q: Evaluate the integral X3 + 6x2 + 3x

A: x3+6x2+3x take integration  y=∫ x3+6x2+3xdx y=∫  x3dx+∫  6x2dx+∫  3xdx

Q: The integral x²/4 - x²dx can be determined using the substitution 4- x2 = t.

A: Given integral: ∫02x24-x2dx

Q: 1 x²(x3 - 4)³ of xp

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Q: Evaluate the integral: 9x - 5 S dx 9x² 18x + 13 —

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Q: Evaluate the integral -4x 1 - x2 1-x2

A: to solve the given indefinite integral put,

Q: Find the indefinite integral J(-16r² – 4x + 6)dr. a. -12r-4x + 6r +C b. -4x*- 2r+ áx +c c. -4x-2r+…

A: Solve the following

Q: Evaluate the integral S6x/( x²+1)(2x-2).

A:

Q: Evaluate the integral. 0.8 V 16 - 25x2

A: The given integral is  ∫00.8x216-25x2dx

Q: Evaluate the definite integral. 2x2 + 2 = rp

A: Topic:- calculus

Q: Find the indefinite integral. Vx +8 xp- 3 7 2 Vx +8 6 6 4 3 - X- 35 + + C X- .3 15

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Q: Evaluate the integral. to dt 5/2 x2 (x² – 16}"-

A: Given:  ∫ x2 dxx2 -1652 =?Using Substittution Method:…

Q: (x²–1) 2.

A: