Find the vector form of the equation of the line that passes through the points (1,-3,2) and (4,2,-1). A. * = (1+ 4t, –3+ 2t, 2 – t) В. 3 (1—36, -3 — 5t, 2 + 3€) С. 3D (4 — 3t, 2- 5t, —1 + t) D. = (4+t,2 – 3t, –1+2t) E. none of the above

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 29E
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Find the vector form of the equation of the line that
passes through the points (1,-3,2) and (4,2,-1).
A. 7 = (1+4t, –3+ 2t, 2 – t)
В. т3 (1—3t, -3 -5t, 2 + 31)
С. 3D (4 — 3t, 2 - 5t, —1 + t)
D. F = (4 +t, 2 – 3t, –1+ 2t)
E. none of the above
Transcribed Image Text:Find the vector form of the equation of the line that passes through the points (1,-3,2) and (4,2,-1). A. 7 = (1+4t, –3+ 2t, 2 – t) В. т3 (1—3t, -3 -5t, 2 + 31) С. 3D (4 — 3t, 2 - 5t, —1 + t) D. F = (4 +t, 2 – 3t, –1+ 2t) E. none of the above
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