Find x . 24 ft 10 ft ft

Q: Find the Area. 4.5 mi 8 mi Area=

A: Area of Triangle = 1/2 * base * height                   here in this Question…

Q: 5 ft Surface Area: ft? Blank 1:

A: objective is to find the surface area

Q: 24 mi Find the Area: area. rds ase

A: We have to find area

Q: Determine the shaded area. 2 ft

A:

Q: 39 yd 52 yd

A:

Q: Sxcos²2x dx

A: Given: ∫xcos22xdx

Q: 6 yd 11 yd

A:

Q: 15 ft 21 ft 24 ft Perimeter %3D

A:

Q: Find the Area. 22 ft 23 ft 37 ft Area=

A:

Q: 18 yd 35 yd 69 yd

A: Area = 936 square unit

Q: area =75 y'bs ft. Area =. %3D Width =

A: Length is 15 ft ,see the explanation in step 2.

Q: Find the value of x. 107 ft 40°

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Q: E 92 200 F D

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Q: 11 ft ft (v- 25) ft 11 ft

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Q: 8 ft 5 ft -64 ft y

A: The figure of the triangle is given by To evaluate : The value of y

Q: C 30 feet E 25 feet 15 feet A. В

A:

Q: 4. 12 ft 10 ft 73t 5 t 9 ft

A: The given prism has dimensions 9 ft, 5 ft, 10 ft, 12 ft and 7.3 ft. we have to find its volume

Q: 380 ft 490 ft 310 ft 226 ft

A: Given: A quadrilateral divided into two triangles. In the right-angled triangle,…

Q: Determine the shaded area. 14 ft

A:

Q: 23 meters per second = ___ miles per hour.

A:

Q: Give the boundaries of the indicated value. 172 feet

A: We need to find indicated values.

Q: Determine the shaded area. 13 yd 7 yd 10 yo 14 yd

A: Outer figure is trapezoid with length of parallel side are 7 yd and 13 yd and height of trapezoid is…

Q: Find the Area. 16 ft 12 ft 6 ft Area=

A: Area of the trapezoid is given by A=a+b2h Where and b are lengths of parallel sides h is height

Q: Find the length of the leg x. Round to the nearest hundredth. 10 8 X =

A: As we know that Pythagoras theorem: Hypotenuse2=Perpendicular2+Base2 From the given figure:…

Q: Shima walked 36 mile. Convert this distance to kilometers. kilometers

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Q: 2. 2 mi = yd %D

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Q: Find p. C 6 ft 4 ft 4 ft

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Q: Determine x to the nearest tenth of a metre. 4.6 m 77° 6.3 m

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Q: 7. (xft. 124 ft. 3

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Q: G 4.3 520 H F

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Q: Find the length of x to the nearest tenth. 13.4 inches 63°

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Q: Determine the width of the pond. x ft. 90 ft. 135 ft. 120 ft

A: Consider a triangle- To find width of the pond that is value of x From figure it can be seen that -…

Q: Find the area of the Circie below: H0 km

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Q: Determine the shaded area. 12 ft

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Q: 5.5 ft 4 ft 24 ft

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Q: 12,000 ft 1) Find x. 22°

A: using trigonometric identity

Q: 10 feet E is

A:

Q: Find the area of the figure. 12 ft 5 ft 2 ft 5 ft 18 ft Area ft2

A: First break the figure then use area formula

Q: 3. 9 ft t 26 ft

A: Solution:To find the area of the given figureArea=Area of semi circle+Area of triangle+Area of…

Q: Determine the shaded area. 9 ft

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Q: ft 41° 15 ft

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Q: 12 ft 10 ft

A:

Q: Determine the shaded area. 11 ft

A: The area of the shaded region is, 121(4 - π) ft² or, 103.87 ft²

Q: 4 yd 15 yd 7 yd

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Q: Find the value of x. 580 yd

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Q: Determine the shaded area. 16 yd 12 yd 14 yd 24 yd

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Q: 6 ft

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Q: 10 m 10 m 10 m 10 m 16 m

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Q: Find the missing side: 10 yd 11 yd

A: By using Pythagoras theorem, we calculate the value of 'x'