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Find y' where y = (tan(18z² +5)) / 18z3 +14 Answer: 54z2 O v' = sec2 (36z) /1823 + 14 + tan(182² + 5)- 2/18z3 + 14 5422 O y' = 36z sec2 (18z² + 5)- 2/1823 + 14 1. y' = sec2 (1822 + 5) /18z3 + 14+ tan(1822 + 5)- 2/18z3 + 14 54,2 O' = 36z tan(18z² + 5) /18z3 + 14+ tan(18z² + 5)- 2/1823 +14 54,2 O = 36z sec? (1822 + 5) V/1823 + 14+ tan(18z² + 5)- 2/1823 + 14

Find y' where y = (tan(18z² +5)) / 18z3 +14 Answer: 54z2 O v' = sec2 (36z) /1823 + 14 + tan(182² + 5)- 2/18z3 + 14 5422 O y' = 36z sec2 (18z² + 5)- 2/1823 + 14 1. y' = sec2 (1822 + 5) /18z3 + 14+ tan(1822 + 5)- 2/18z3 + 14 54,2 O' = 36z tan(18z² + 5) /18z3 + 14+ tan(18z² + 5)- 2/1823 +14 54,2 O = 36z sec? (1822 + 5) V/1823 + 14+ tan(18z² + 5)- 2/1823 + 14

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find y' where y = (tan(18z² +5)) / 18z3 +14 Answer: 54z2 O v' = sec2 (36z) /1823 + 14 + tan(182² + 5)- 2/18z3 + 14 5422 O y' = 36z sec2 (18z² + 5)- 2/1823 + 14 1. y' = sec2 (1822 + 5) /18z3 + 14+ tan(1822 + 5)- 2/18z3 + 14 54,2 O' = 36z tan(18z² + 5) /18z3 + 14+ tan(18z² + 5)- 2/1823 +14 54,2 O = 36z sec? (1822 + 5) V/1823 + 14+ tan(18z² + 5)- 2/1823 + 14
Transcribed Image Text:Find y' where y = (tan(18z² +5)) / 18z3 +14 Answer: 54z2 O v' = sec2 (36z) /1823 + 14 + tan(182² + 5)- 2/18z3 + 14 5422 O y' = 36z sec2 (18z² + 5)- 2/1823 + 14 1. y' = sec2 (1822 + 5) /18z3 + 14+ tan(1822 + 5)- 2/18z3 + 14 54,2 O' = 36z tan(18z² + 5) /18z3 + 14+ tan(18z² + 5)- 2/1823 +14 54,2 O = 36z sec? (1822 + 5) V/1823 + 14+ tan(18z² + 5)- 2/1823 + 14
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