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Find y': y = arctan(e2x) 2e2x y 1– e4x? 2e2x y = 1 – e4x %3D 2e2x y 1 + e4x %3D 2e2x y 1 + e4x2

Find y': y = arctan(e2x) 2e2x y 1– e4x? 2e2x y = 1 – e4x %3D 2e2x y 1 + e4x %3D 2e2x y 1 + e4x2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find y': y = arctan(e2x) 2e2x y = 1 – etx? 2e2x 1 – e4x 2e2x y 1 + e4x 2e2x 1 + e4x?
Transcribed Image Text:Find y': y = arctan(e2x) 2e2x y = 1 – etx? 2e2x 1 – e4x 2e2x y 1 + e4x 2e2x 1 + e4x?
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