Find y(t) solution of the initial value problem ty' - y + 5t² cos(3t) = 0, None of the options displayed. y(t) = t cos(3t) y(t) y(t) = 5 3 5 t (1 - sin(3t)) t cos(3t) 3 | y(t) = t (1 — sin(3t)) Oy(t) = cos(3t) Oy(t) = 1 - sin(3t) y (7)=0, t>0.

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