Please use python • find_solvable_blackout_equation(num_tries, n, pct_per_digit): Takes one positive integer, onepositive odd integer, and one float in [0, 1[ as input. Randomly creates and returns a solvableBlackout Math equation of length n and with each number having the given percent chance to havemore than one digit. If such an equation cannot be generated after the given number of tries, thenreturn None instead.>>> random. seed(42)>>> find_solvable_blackout_equation(1000, 7, 0.2)[37, '+', 9, '=', 1, 'x', 6]>>> random.seed(1337)>>> find_solvable_blackout_equation(1000, 13, 0.25)[9, '/', 3, /', 6, '=', 4, '/', 71, '-', 6, '+', 5]

from blackout_utils import * import random OPERATIONS = ['^', 'x', '/', '+', '-'] def…

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COMPREHENSIVE MICROSOFT OFFICE 365 EXCE

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ISBN:9780357392676

Author:FREUND, Steven

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Chapter6: Creating, Sorting, And Querying A Table

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Version:0.9 StartHTML:0000000105 EndHTML:0000002393 StartFragment:0000000141 EndFragment:0000002353 A smaller bucket with capacity 1 (unit of volume) is used to fifill a larger bucket with capacity v (units of volume). A farmer successively draws water from a well using the smaller bucket and poors the content in the larger bucket. Suppose the successive amounts of water taken out of the well form a sequence of independent uniform over [0, 1] random variables. (a) On average, how many times will the farmer have to draw water out of the well to fifill the larger bucket if its volume is v = 1? (b) Repeat for v = 2.
Solve the following for an input.txt file containing the following: "1 2 3 4" #include <stdio.h>#include <stdlib.h>void end_now();char *next_input(); int hash = 8765309;int INPUTS[4]; void phase03(){ // TODO: put numbers in input.txt to pass the code below int a = atoi(next_input()); int b = atoi(next_input()); int c = atoi(next_input()); int d = atoi(next_input()); int targ = 0; targ |= 1 << (hash % 13); targ = targ << (hash % 3); targ |= 1 << (hash % 19); targ = targ << (hash % 5); targ |= 1 << (hash % 31); targ = targ << (hash % 7); int shot = 0; shot |= 1 << a; shot |= 1 << b; shot |= 1 << c; shot |= 1 << d; int hit = shot ^ targ; hit = !hit; if(hit){ printf("Right on target: nice shootin' bitslinger!\n"); return; } printf("Shifty bits hit? Xor not it seems...\n"); end_now();} ////////////////////////////////////////////////////////////////////////////////// additional code to…
BY USING PYTHON The file100000 in question 2 is shown in question 1. QUESTION 2: Perform a benchmark analysis of the following searching methods:- Linear (Sequential) Search- Binary Search- Hashing Read the file “file100000” into a list. Sort the file using the one of fast sorting algorithms. You can use orderedSequentialSearch, binarySearch, and HashTable code given in https://runestone.academy/runestone/books/published/pythonds/SortSearch/toctree.html. Fill the hash table with key values stored in the file100000. The data values mapping to the key values can be assigned to a string like “Data” + str(key). Make the hash table size 10% bigger. For example you can set self.size = 110017 which is a prime number.Generate a list of 1000 random numbers using random.randint(0,100000). By using the searching methods, make a search of these random numbers. Record their total execution times into a file named “searchStats.txt”. The “searchStats.txt” file should contain entries for…
import numpy as np # Given current stock pricecurrent_price = 163.02 # Simulate future stock pricesnum_samples = 1000 # You can adjust this number based on your needsgrowth_rate_samples = np.random.lognormal(mean=-0.8404, sigma=2.5, size=num_samples)future_prices = current_price * np.exp(growth_rate_samples) # Print or visualize the simulated future pricesprint(future_prices) i cant get an answer , im keeping errors
I need to solve these two methods package algs52; // section 5.2import java.util.HashSet;import stdlib.*; // Create a spell checker that find all "misspelled" words (e.g. non-existing words). // Compare performance of the TST and Trie on various dictionary sizes. // Download and install the following files into your algs4/data directory:// - https://introcs.cs.princeton.edu/java/data/commonwords.txt 74K words// - https://introcs.cs.princeton.edu/java/data/wordlist.txt 224K words// - https://introcs.cs.princeton.edu/java/data/words.utf-8.txt 645K words//// Expected output should be similar in performance://// TrieST | TST// Words Time | Words Time %// 23699 0.40 | 23699 0.18 43%// 25913 0.53 | 25913 0.34 63%// 18075 1.15 | 18075 0.86 74% public class hw4{public static HashSet<String> TrieFilter(String dictionary_file, String text_file) { // TODO: Create a Trie from the dictionary, and find all non-existing words in the input text file. HashSet<String>…
Sort by reverse domain: Write a data type Domain that represents domain names,including an appropriate compareTo() method where the natural order is in order ofthe reverse domain name. For example, the reverse domain of cs.princeton.edu isedu.princeton.cs. This is useful for web log analysis. Hint: Use s.split("\\.") tosplit the string s into tokens, delimited by dots. Write a client that reads domain names from standard input and prints the reverse domains in sorted order
Write a program that will use the hash function “H (key) =key mod 20” to create bank application that stores the below information of customer in the hash table of size =20. Account Number (Key) must be 4 digits value and generated by user defined random function .Compare its performance with linear probing, quadratic probing. If you use “cubic probing”; here the ith probe is at hash(x) + i3 . Does cubic probing improve the performance over linear probing and quadratic probing?  key  name  account title  balance  status
Solve this and make sure the code compiles orderdp.cpp: #include <fcntl.h> #include <stdlib.h> #include <unistd.h> #include <inttypes.h> #include "orders.h" item::item(uint16_t s, uint16_t q) : sku(s), quantity(q) { } item_list::item_list() : items(NULL), num_products(0) { } void item_list::add(const item& i) { items = (item**)realloc(items, (num_products+1)*sizeof(item*)); items[num_products] = new item(i); num_products++; } order::order(uint16_t o, std::string n) : order_id(o), customer_name(n) { } void order::addItem(const item& i) { product_items.add(i); } order** read_orders(const char* filename, uint16_t* num_orders) { int fd; fd = open(filename, O_RDONLY); int err = fd; if (err == -1) { return NULL; } read(fd, num_orders, sizeof(*num_orders)); order** orders = new order*[*num_orders]; for (int i=0; i<*num_orders; i++) { uint16_t order_id; uint16_t num_products;…
Write a python program to: Find all rows with a title of "Limitless" Find all rows with a director of "Robert Rodrigues" and a type of "Movie" Find all rows with either a date_added of "2019-07-31" or director of "Robert Altman" Find all rows with a director of "Orson Welles","Aditya Kripalani" or "Sam Raimi". Find all rows that have a date_added value between May 1, 2019 and June 1,2019 Drop all rows with a NaN value in the director column. Identify all days when only one movie was added to Netflix catalog. Note: the question come with a csv file that contains all the necessary data. the csv file looks like this
Which of the following two arrays will Mergesort method sort more efficiently? A) { 5,4,7,9,8,10,3,2,6,1} B) { 4,4,4,4,4,4,4,4,4,4} Question 9 options: Neither) Mergesort runs in the same amount of time regardless of the ordering of the array. A) Mergesort will sort a randomized array in nLog(n) time and an array of duplicates in n^2 time. B) Because our array is all duplicates, Mergesort will recognize that it is already sorted and exit early.
Substitution ciphers are encryption/decryption algorithms that replace one letter or number with another. The first attested use of a substitution cipher in military affairs was by Julius Caesar, described by him in Gallic Wars (cf. Kahn pp83-84). In caesar cipher , you replace each letter by 3rd letter on. If it is out of bound (later than Z), then round to the head (letter A) and continue the shift. For example:meet me after the toga party PHHW PH DIWHU WKH WRJD SDUWB Please write a program in Java to implement the Caesar Cipher: a. Implement the encryption algorithm. Ask the user to input one all lower case normal sentence (called plaintext) using the nextLine method, and then output the encrypted text (called ciphertext). b. Implement the decryption algorithm. Ask the user to input one encrypted sentence (i.e. ciphertext) using the nextLine method, and then output the decrypted text (i.e. plaintext).
My question is to modify binary search to only display the result with book title with its ID number. Here is the code to modify: def search_books(self, book_title): # Remove leading and trailing white spaces and convert to lowercase book_title = book_title.strip().lower() # Extract book titles and IDs from self.books_dict book_titles = [value["books_title"].strip().lower() for key, value in self.books_dict.items()] #book_ids = list(self.books_dict.keys()) # Sort the book titles and IDs together book_titles, book_ids = zip(*sorted(zip(book_titles, book_ids))) #zip takes iterable or containers and return a single iterator # Perform binary search for the book title low = 0 high = len(book_titles) - 1 while low <= high: mid = (low + high) // 2 bt = book_titles[mid].replace('"', '') if bt == book_title: print(f"Book '{book_title}'…

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