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Finding the root of a quadratic equation with leading coefficient5u2=-9u-4Can someone please help me with the step-by-step process of solving this problem please?If there is more than one solution, separate them with commas. Thank you.

Question

Finding the root of a quadratic equation with leading coefficient

5u2=-9u-4

Can someone please help me with the step-by-step process of solving this problem please?

If there is more than one solution, separate them with commas. 

Thank you.

check_circleAnswer
Step 1

Given,

 

5u' %3D —9и — 4
3 - 9и — 4
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5u' %3D —9и — 4 3 - 9и — 4

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Step 2

On simplification, we g...

5u 9u4 0
Comparing with ax bx +c 0, we get
a 5, b 9 and c 4
Now the product of roots = a c = 5.4 20
Sum of roots b =9
. Su 5u4u 4 = 0
Su(u+1)+ 4(u+1)= 0
(u+1)(5u+4) 0
u10 or 5u +4 = 0
4
u-1 or u =
5
help_outline

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5u 9u4 0 Comparing with ax bx +c 0, we get a 5, b 9 and c 4 Now the product of roots = a c = 5.4 20 Sum of roots b =9 . Su 5u4u 4 = 0 Su(u+1)+ 4(u+1)= 0 (u+1)(5u+4) 0 u10 or 5u +4 = 0 4 u-1 or u = 5

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