First find the equation of a plane through the point (4, 2, 1) with normal vector = 3i - 2j+ 4k. Next find the equation of the line through this same point (4, 2, 1) and with direction parallel to this normal vector = 37-2j+4k. (this line is called the normal line to the plane) Now graph both this plane and the normal line together. 10 ܝ ܐ ܕ ܝ ܝ ܝ 10 سك

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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First find the equation of a plane through the point (4, 2, 1) with normal vector = 3ī − 2j + 4k.
Next find the equation of the line through this same point (4, 2, 1) and with direction parallel
to this normal vector i = 3ī −2j+ 4k. (this line is called the normal line to the plane)
Now graph both this plane and the normal line together.
10
ستید
10
تند
مسك
Transcribed Image Text:First find the equation of a plane through the point (4, 2, 1) with normal vector = 3ī − 2j + 4k. Next find the equation of the line through this same point (4, 2, 1) and with direction parallel to this normal vector i = 3ī −2j+ 4k. (this line is called the normal line to the plane) Now graph both this plane and the normal line together. 10 ستید 10 تند مسك
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