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First, recall that sin²2 (0) = 1 - cos² (0). Thus, substitute (1 - cos²(0)) for sin²(0) in the given equation. Then, simplify. 2 sin²(0) - cos(0) = 1 cos² (0)) - cos(0) = 1 cos² (0) cos(0) - 1 = 0 cos² (0) cos(0) + 1 = 0 2([ 2-

First, recall that sin²2 (0) = 1 - cos² (0). Thus, substitute (1 - cos²(0)) for sin²(0) in the given equation. Then, simplify. 2 sin²(0) - cos(0) = 1 cos² (0)) - cos(0) = 1 cos² (0) cos(0) - 1 = 0 cos² (0) cos(0) + 1 = 0 2([ 2-

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 88E
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First, recall that sin²2 (0) = 1 - cos² (0). Thus, substitute (1 - cos²(0)) for sin²(0) in the given equation. Then, simplify. 2 sin²(0) - cos(0) = 1 cos² (0)) - cos(0) = 1 cos² (0) cos(0) - 1 = 0 cos² (0) cos(0) + 1 = 0 2([ 2-
Transcribed Image Text:First, recall that sin²2 (0) = 1 - cos² (0). Thus, substitute (1 - cos²(0)) for sin²(0) in the given equation. Then, simplify. 2 sin²(0) - cos(0) = 1 cos² (0)) - cos(0) = 1 cos² (0) cos(0) - 1 = 0 cos² (0) cos(0) + 1 = 0 2([ 2-
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