Five keys 8, 25, 10, 15, 18 have been added to a hash table of size 4 that uses Separate Chaining using hash function h(x) resultant hash-table. = x % 4. Show the You have to insert two more keys 43 and 92 into the hash table. The designer of the hash table decided to resize the table by doubling its size when the load factor reaches or exceeds 1.5. Draw the new hash table after the insertions. The keys 2222, 1118, 1323, 2, 343, 2133, 155 and 95 are inserted into an initially empty hash table of length 10 using open addressing with hash function h(k) = k mod 10 with linear probing. What is the resultant hash table? %3D

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
icon
Related questions
Question
100%
Five keys 8, 25, 10, 15, 18 have been added to a hash table of size 4 that
uses Separate Chaining using hash function h(x)
resultant hash-table.
= x % 4. Show the
You have to insert two more keys 43 and 92 into the hash table. The
designer of the hash table decided to resize the table by doubling its size
when the load factor reaches or exceeds 1.5. Draw the new hash table
after the insertions.
The keys 2222, 1118, 1323, 2, 343, 2133, 155 and 95 are inserted into an
initially empty hash table of length 10 using open addressing with hash
function h(k) = k mod 10 with linear probing. What is the resultant hash
table?
Transcribed Image Text:Five keys 8, 25, 10, 15, 18 have been added to a hash table of size 4 that uses Separate Chaining using hash function h(x) resultant hash-table. = x % 4. Show the You have to insert two more keys 43 and 92 into the hash table. The designer of the hash table decided to resize the table by doubling its size when the load factor reaches or exceeds 1.5. Draw the new hash table after the insertions. The keys 2222, 1118, 1323, 2, 343, 2133, 155 and 95 are inserted into an initially empty hash table of length 10 using open addressing with hash function h(k) = k mod 10 with linear probing. What is the resultant hash table?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 3 images

Blurred answer
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY