f(M1) = 0.6 and f(M2) = 0.4. We found %3D out that 25% of the M1M1 individuals survive, 50% of the M1M2 individuals survive, and 100% of the M2M2 individuals survive. We let those individuals that survive mate and reproduce.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Same population
f(M1) = 0.6 and f(M2) = 0.4. We found
out that 25% of the M1M1 individuals
survive, 50% of the M1M2 individuals
survive, and 100% of the M2M2
individuals survive. We let those
individuals that survive mate and
reproduce.
For
your calculations, use a finite
population size of
and each
contribute 10 gametes to the next
generation.
**Hint: this question is done exactly
the same process as in my lecture
Natural Selection Part 3
What are the new allele frequencies?
M1 = 0.6
M2 = 0.4
M2 = 0.5
M1 = 0.5
M2 = 0.6
M1 = 0.4
Transcribed Image Text:Same population f(M1) = 0.6 and f(M2) = 0.4. We found out that 25% of the M1M1 individuals survive, 50% of the M1M2 individuals survive, and 100% of the M2M2 individuals survive. We let those individuals that survive mate and reproduce. For your calculations, use a finite population size of and each contribute 10 gametes to the next generation. **Hint: this question is done exactly the same process as in my lecture Natural Selection Part 3 What are the new allele frequencies? M1 = 0.6 M2 = 0.4 M2 = 0.5 M1 = 0.5 M2 = 0.6 M1 = 0.4
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