Following are the results of a filed unit weight determination test on soil with the sand cone method: Calibrated dry density of Ottawa Sand = 1667kg/m³ Calibrated mass of Ottawa sand to fill the cone =0.177kg Mass of jar + cone + sand (before use) = 5.99kg Mass of jar + cone + sand (after use) = 2.81kg Mass of soil from hole = 3.331kg Moisture content of moist soil = 11.6% 38. Determine the dry unit weight of soil in the field. (kN/m³) с. 17.78 а. 18.56 b. 20.45 d. 16.25 39. If the maximum dry unit weight of the soil is, 17.54KN/m³, calculate the relative compaction. a. 92.67% b. 86.52% С. 88.97% d. 95.45%

Following are the results of a filed unit weight determination test on soil with the sand cone method: Calibrated dry density of Ottawa Sand = 1667kg/m³ Calibrated mass of Ottawa sand to fill the cone =0.177kg Mass of jar + cone + sand (before use) = 5.99kg Mass of jar + cone + sand (after use) = 2.81kg Mass of soil from hole = 3.331kg Moisture content of moist soil = 11.6% 38. Determine the dry unit weight of soil in the field. (kN/m³) с. 17.78 а. 18.56 b. 20.45 d. 16.25 39. If the maximum dry unit weight of the soil is, 17.54KN/m³, calculate the relative compaction. a. 92.67% b. 86.52% С. 88.97% d. 95.45%

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.7P

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The following are the results of a field unit weight determination test performed on the soil by means of the sand cone method. Calibrated dry density of Ottawa sand = 1570 kg/m3 Calibrated mass of Ottawa sand to fill the cone = 0.545 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil dug from hole = 3.007 kg Water content of moist soil = 10.2% Max dry unit weight = 19 kN/m3 Find the dry unit weight in kN/m3.
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30, PL = 10) ? Use this given M=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 gM=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 g Sieve No. Opening Size (mm) Mass retained (g) %Mass retained=MiM×100=MiM×100 %Cumulative mass retained % Finer 4 4.750 28 =28617×100%=4.54%=28617×100%=4.54% 4.54 95.46 10 2.0 42 =42617×100%=6.81%=42617×100%=6.81% 11.35 88.65 20 0.850 48 =48617×100%=7.78%=48617×100%=7.78% 19.13 80.87 40 0.425 128 =128617×100%=20.74%=128617×100%=20.74% 39.87 60.13 60 0.250 221 =221617×100%=35.82%=221617×100%=35.82% 75.69 24.31 100 0.150 86 =86617×100%=13.94%=86617×100%=13.94% 89.63 10.37 200 0.075 40 =40617×100%=6.48%=40617×100%=6.48% 96.11 3.89 Pan 24 =24617×100%=3.89%=24617×100%=3.89% 100 0 Now, to plot the GSD curve, the % finer is kept on the vertical axis and the opening size are kept on the horizontal axis -…
A soil sample has the following properties: Sp.gr. = 2.67, Void ratio = 0.54, Water content = 11.2%. Compute the air void ratio.
Undisturbed soil obtained from a test pit 0.0283 m3 (1 ft3) in volume is found to have a wet weight of 0.459 kN (103.2 lb). The dry weight of the sample is 0.376 kN (84.5 lb). What would be the effective unit weight of such a soil if it were submerged below the groundwater table? The specific gravity of the soil is determined to be 2.70.
From a particle size distribution curve of a sandy soil the following were obtain: Size of particle 0.48 mm percentage finer 60;Size of particle 0.33 mm percentage finer 30;Size of particle 0.21 mm percentage finer 10;Size of particle 0.11 mm percentage finer 5;Determine Cc.
A fully saturated soil sample has a volume of 28 cc. The sample was dried in oven and the weight of the dry soil pat was found to be 48.76 g. Given G= 2.68. Determine void ratio in percent. a. 18.23 b. 53.6 c. 9.77 d. 20.0
with figures if necessary 1. A wet sand sample has a volume of 4.64 x 10-4 m3 and weighs 8 N. After oven-drying, the weight reduces to 7.5 N. Calculate the water content, void ratio, and degree of saturation. 2. The mass of a wet sample of soil and its container is 0.33 kg. The dry mass of the soil and its container is 0.29 kg. The mass of the container is 0.06 kg and its volume is 0.15 x 10-3 m3. Determine the bulk, dry and saturated unit weights of the soil. Determine the void ratio and degree of saturation. Determine the amount of air void in the soil and the water of water required to saturate 1 m3 of the soil. 3. A sand has a natural water content of 5% and bulk unit weight of 18.0 kN/m3. The void ratios corresponding to the densest and loosest state of this soil are 0.51 and 0.87. Find the relative density and degree of saturation.
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34 d. 88.41
1.Three phases of a soil element? 2.Define volumetric relations (equation and text):e= , n=, S= 3. Define weight relations (equationand text):w=, Y= , Gs= 4. Range of values for degree of saturation? 5. Range of values for moisture content? 6. Correlation between dry unit weight and total unit weight (use w)? 7.Super equation (label each term)? 8. Unit weight of water ( English,metric)? 9. Average unit weight for medium dense sand? 10.Specific gravity for sand?
A sand-cone in place unit test was conducted on the field during the construction of a proposed embankment. The following data were obtained. moisture content=12.8% weight of sand to fill the funnel=320 g weight of wet soil from test hole=750 g unit weight of sand=15.4 kN/m3 weight of sand used to fill test hole and funnel of sand-cone device=870 g a) compute the wet unit weight of soil (Ans. 21.14 kN/m3) b) compute the dry unit weight of the compacted soil (Ans. 18.74 kN/m3) c) compute the relative compaction in the field if the maximum dry unit weight of the soil is 21.3 kN/m3. (Ans. 87.98%)
The maximum and minimum void ratios for sand are 0.805 and 0.501 respectively. The field density test performed on the same soil has given the following results:ρ = 1.81 g/cm3, w= 12.7 %. Assume G= 2.67. Compute the in situ void ratio. a.0.51 b.0.42 c.0.65 d.0.85