For all x 1 we haveΣ0₁(n) = 5(2)n≤x2-x² + 0(x log x).

We recall some basic facts and then proceed to solve the problem. The detailed solution is given as…

Answered: For all x > 1 we have Στι(n) = 6(2) x2…

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For all x > 1 we have Στι(n) = 6(2) x2 + O(xloga). ηΣα

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section: Chapter Questions

Problem 20T

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Question

For all x 1 we have
Σ0₁(n) = 5(2)
n≤x
2
-x² + 0(x log x).

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