For an alternating series whose summands are decreasing in magnitude, the true sum S lies between any two successive partial sums: Consider S = ∞ n=1 (*) (−1)n+1 n³ Answer: Nmin = and write Answer: S≈ min {SN, SN+1} ≤ S≤ max {SN, SN+1}. (−1)n+1 n³ SN = (a) Find the smallest value of N for which the interval bracketing S in line (*) above has length at most 10-5. SN + SN+1 2 N n=1 (b) Using the N found in part (a), approximate S by the midpoint of the interval implicit in line (*). A spreadshe may be helpful to calculate the sum SN.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 81E
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For an alternating series whose summands are decreasing in magnitude, the true sum S lies between any two
successive partial sums:
Consider S =
n=1
Answer:
(*)
(−1)n+1
n³
Nmin =
and write
Answer: S≈
min {SN, SN+1} ≤ S≤ max {SN, SN+1}.
(−1)n+1
n³
SN
(a) Find the smallest value of N for which the interval bracketing S in line (*) above has length at most 10–5.
SN + SN+1
2
=
N
n=1
(b) Using the N found in part (a), approximate S by the midpoint of the interval implicit in line (*). A spreadsheet
may be helpful to calculate the sum SN.
Transcribed Image Text:For an alternating series whose summands are decreasing in magnitude, the true sum S lies between any two successive partial sums: Consider S = n=1 Answer: (*) (−1)n+1 n³ Nmin = and write Answer: S≈ min {SN, SN+1} ≤ S≤ max {SN, SN+1}. (−1)n+1 n³ SN (a) Find the smallest value of N for which the interval bracketing S in line (*) above has length at most 10–5. SN + SN+1 2 = N n=1 (b) Using the N found in part (a), approximate S by the midpoint of the interval implicit in line (*). A spreadsheet may be helpful to calculate the sum SN.
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