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For an equation like r 0, a root exists atx 0. The Bisection Method cannot be adopted to solve this equation in spite of the root existing at.x 0 because the function f(x)= x (A) is a polynomial (B) has repeated roots at x 0 (C) is always non-negative (D) has a slope equal to zero at x 0

For an equation like r 0, a root exists atx 0. The Bisection Method cannot be adopted to solve this equation in spite of the root existing at.x 0 because the function f(x)= x (A) is a polynomial (B) has repeated roots at x 0 (C) is always non-negative (D) has a slope equal to zero at x 0

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 93E
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For an equation liker =0, a root exists at x = 0. The Bisection Method cannot be adopted to solve this equation in spite of the root existing at.x 0 because the function Ax)= x (A) is a polynomial (B) has repeated roots at x = 0 (C) is always non-negative (D) has a slope equal to zero at x = 0 B OA C OD
Transcribed Image Text:For an equation liker =0, a root exists at x = 0. The Bisection Method cannot be adopted to solve this equation in spite of the root existing at.x 0 because the function Ax)= x (A) is a polynomial (B) has repeated roots at x = 0 (C) is always non-negative (D) has a slope equal to zero at x = 0 B OA C OD
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