For an invertible matrix A, prove that A and A- have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1? Letting x be an eigenvector of A gives Ax = ix for a corresponding eigenvalue 1. Using matrix operations and the properties of inverse matrices gives which of the following? Ax = ix Ах - Ах A/(Ax) = A/(1x) O(A/A)x = (A/a)x Ix = (A/a)x x = 1A-x Ax = ix Ax = ix Ax/A = ix/A (A/A)x = ixA-1 Ix = ixA-1 x = ixA-1 A'Ax = A-1ax Ix = 1A-1x AxA-1 = ixA-1 = A-'x OXA4-1 XI = A-1x x = 1A-1x A-x = 1x x = 1A-x A-x = 1x A-1x = 1x A-ix = 1x This shows that -Select-- v is an eigenvector of A¬1 with eigenvalue -Select---v -Select- -Select-- 1/x 1/x 1/2 1/2

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.3: Eigenvalues And Eigenvectors Of N X N Matrices
Problem 41EQ
icon
Related questions
Question

3.

For an invertible matrix A, prove that A and A- have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1?
Letting x be an eigenvector of A gives Ax = ix for a corresponding eigenvalue 2. Using matrix operations and the properties of inverse matrices gives which of the following?
Ax = ix
Ax = ix
Ax = ix
Ax = ix
Ax/A = ix/A
A/(Ax) = A/(1x)
AXA-1
iXA-1
%3D
%3D
A-'Ax = A-1ix
Ix = AA-1x
%3D
iXA-1
Ix = ixA-1
ixA-1
(A/A)x
O(A/A)x = (A/2)x
OXAA-1
XI =
%3D
(A/2)x
x = 1A-x
1x
Ix =
X =
X =
x =
A-1x = 1x
%3D
A-x = 1x
A-1x =
A-1x = 1x
This shows that --Select-- v is an eigenvector of A with eigenvalue
---Select-- v
-Select---
-Select--
1/x
1/x
1/1
1/1
Transcribed Image Text:For an invertible matrix A, prove that A and A- have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1? Letting x be an eigenvector of A gives Ax = ix for a corresponding eigenvalue 2. Using matrix operations and the properties of inverse matrices gives which of the following? Ax = ix Ax = ix Ax = ix Ax = ix Ax/A = ix/A A/(Ax) = A/(1x) AXA-1 iXA-1 %3D %3D A-'Ax = A-1ix Ix = AA-1x %3D iXA-1 Ix = ixA-1 ixA-1 (A/A)x O(A/A)x = (A/2)x OXAA-1 XI = %3D (A/2)x x = 1A-x 1x Ix = X = X = x = A-1x = 1x %3D A-x = 1x A-1x = A-1x = 1x This shows that --Select-- v is an eigenvector of A with eigenvalue ---Select-- v -Select--- -Select-- 1/x 1/x 1/1 1/1
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Recommended textbooks for you
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
Algebra
ISBN:
9781305658004
Author:
Ron Larson
Publisher:
Cengage Learning