For arbitrary a and b, c % m = (a b) % m c % m = [(a % m) (b % m)] % m Using this mathematical property, you can iterate 1 to the exponent, recalculating each time by multiplying the current modulus value with the last. Here is the pseudocode: 1 Set value = 1, current exponent = 0. 2 Increment current exponent by 1. 3 Set value = (base value) mod modulus until current exponent is reached exponent Example: Base: 4, Exponent: 3, Modulus: 5 4ˆ3 % 5 = 64 % 5 = 4 value = (lastValue x base ) % modulus: value = (1 x 4) % 5 = 4 % 5 = 4 value = (4 x 4) % 5 = 16 % 5 = 1 value = (1 x 4) % 5 = 4 % 5 = 4 write javascript code ?

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter2: Problem Solving Using C++using
Section2.4: Arithmetic Operations
Problem 6E
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For arbitrary a and b,
c % m = (a b) % m
c % m = [(a % m) (b % m)] % m
Using this mathematical property, you can iterate 1 to the exponent, recalculating each time by multiplying the current modulus value with the last.
Here is the pseudocode:
1 Set value = 1, current exponent = 0.
2 Increment current exponent by 1.
3 Set value = (base value) mod modulus until current exponent is reached exponent
Example: Base: 4, Exponent: 3, Modulus: 5
4ˆ3 % 5 = 64 % 5 = 4
value = (lastValue x base ) % modulus:
value = (1 x 4) % 5 = 4 % 5 = 4
value = (4 x 4) % 5 = 16 % 5 = 1
value = (1 x 4) % 5 = 4 % 5 = 4
write javascript code ?

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