for éach given parallelogram. A. Given: Rhombus ARMY with diagonals AM and RY M Prove: AM 1 RY Statement Reason Rhombus ARMY with diagonals AM and RY AR = RM = MY = YA AM and RY bisect each other at D. (3) RD RD (5) Given (1) (2) Definition of bisector (4) SSS Postulate (6) Z1 and 2 form a linear pair. (8) СРСТС (7) Linear Pair Postulate Iftwo angles are both congruent and supplementary, then t are right angles. (9) (10) AM I RY

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter5: Similar Triangles
Section5.5: Special Right Triangles
Problem 22E: Given: Rhombus ABCD not shown in which diagonals AC and DB intersect at point E; DB=AB=8 Find: AC
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Question
Complete the proof for each given parallelogram.
R
A. Given: Rhombus ARMY with diagonals AM and RY
A-
M
D 3
Prove: AM 1 RY
Statement
Reason
Rhombus ARMY with diagonals AM and RY
AR = RM = MY= YA
AM and RY bisect each other at D.
Given
(1)
(2)
Definition of bisector
(4)
SSS Postulate
(3)
RD = RD
(5)
(6)
CPCTC
Z1 and 22 form a linear pair.
(7)
Linear Pair Postulate
(8)
Iftwo angles are both congruent and supplementary, then they
are right angles.
(9)
(10)
AM I RY
Transcribed Image Text:Complete the proof for each given parallelogram. R A. Given: Rhombus ARMY with diagonals AM and RY A- M D 3 Prove: AM 1 RY Statement Reason Rhombus ARMY with diagonals AM and RY AR = RM = MY= YA AM and RY bisect each other at D. Given (1) (2) Definition of bisector (4) SSS Postulate (3) RD = RD (5) (6) CPCTC Z1 and 22 form a linear pair. (7) Linear Pair Postulate (8) Iftwo angles are both congruent and supplementary, then they are right angles. (9) (10) AM I RY
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