Question
Asked Dec 23, 2019
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For Exercise, find three ordered triples that are solutions to the linear equation in three variables.

2x + 4y − 6z = 12

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Expert Answer

Step 1

Given,

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2x + 4y – 6z =12

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Step 2

To find the ordered triplets that are solutions to given equation, we choose some...

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Let x = 0 and y =1 then given equation becomes 2(0)+ 4(1) – 6z = 12= 4– 6z = 12=6z = -8= z = (0.1.-) is the solution of given equation. ,1, 3 Let x =1 and y = 2 then given equation becomes 2(1)+ 4(2)– 6z =12=2+8-6z = 12= 6z =-2=z =-. {1.2.) is the solution of given equation. 3 .1, 2, Let x = 2 and y =3 then given equation becomes 2(2)+ 4(3)– 6z = 12= 4 +12- 6z =12= 6z = 4=z= 3 (2,.3.) is the solution of given equation. 4- 3.

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Tagged in

Math

Algebra

Equations and In-equations