For Exercise, use A = -4 and solve for X 4 and B = -2. [6 A + 5X = B

Q: For Exercise, solve for the indicated variable. t2 for v2 S2V2 S¡V1

A: Given:

Q: Solve for X in the equation, given(a) X = 3A − 2B (b) 2X = 2A − B (c) 2X + 3A = B (d) 2A + 4B = −2X

A: Given:

Q: For Exercise, solve for the indicated variable. 16 + Vr – y = z for.

A:

Q: For Exercise, make an appropriate substitution and solve the equation. 4 + 1 = 0 -- х

A:

Q: Mrs. Sanders asked the class to solve for x. What answer should the students come up with? 2x 4x-2 2…

A:

Q: Given the following two equations, solve for x: y = 6 + 10 x y = 3 x =

A:

Q: Identify the steps you would use to solve for y? x + 2y = 12

A: Given,         The equation is x+2y=12 .

Q: Solve the following equation x²+3x+2-i = 0

A:

Q: Solve the following equation for x: 4x - b = 2x + c

A: 4x-b=2x+c4x-2x=b+c

Q: Solve the following equation by making an appropriate substitution. (x2-4x)2-17(x2-4x)+60=0

A: x2-4x2-17(x2-4x)+60=0         →(1) we have to simplify this using substitution method.

Q: For Exercise, solve the equation. e* – 9e* = 4 2

A: To solve the given equation.

Q: Solve the following equations for x: a) 2e6 = 18 b) 2x = e5 c) 2 x-2 = 5

A: The detailed solution is given below Thank you

Q: For Exercise, solve the equation. 6 = 9 + V5 – 3x

A:

Q: For Exercise, solve the equation. V2n + 29 + 3 = n

A:

Q: The formula occurs in the indicated application. Solve for the specified variable.

A: Given: 1R = 1R1 + 1R2 + 1R3  To solve: The given expression for the variable R2.

Q: For Exercise, solve for the indicated variable. P¡V1 T1 P2V2 for T1 T2

A: We cross multiply both sides

Q: Solve the equation for x.   3/4(12x + 4) = 30   A) 3     B) 5     C) 7     D) 12

A: To Determine: Solve for x.

Q: For Exercise, solve the equation. x + 1) - 2 3" 1) –

A: Given expression

Q: For Exercise, solve the equation.  7 = 5 − 2(4q − 1)

A: We need to solve the equation 7 = 5 − 2(4q − 1).

Q: Solve the equation -3X + A = B for X, given that and B = [ 2 -5 –1

A:

Q: Given another equation x- y = 2 2.2.1 Put x = 0 and solve fory

A:

Q: Solve the equation for the indicated variable.

A: Given- ax+bcx+d-2 To solve- The above equation for the indicated variable x.

Q: -4 and solve for X. For Exercise, use A = and B = -2 9. 3X + A = B

A:

Q: For Exercise, make an appropriate substitution and solve the equation. +- +1 = 0 -- at a

A: Let  Then substitute this in the given equation Use quadratic formula to find x

Q: For Exercise, solve the equation. 1 = 3 + V2r + 7

A: Subtract 3 from both sides

Q: Solve the following equation by making an appropriate substitution. x-2+7x-1-18=0

A:

Q: For Exercise, solve the equation. x + 3 :- 4 + 2 = 5х х

A: LCM of the denominators is =5x So to get rid of the fractions we multiply both sides by 5x.

Q: For Exercise, solve the equation. 5m 3 т — 1 т + Зт — 4 т+4

A: Given,

Q: For Exercise, solve the equation. 10* – 13 · 10* 3

A:

Q: For Exercise, use A = and B = -4 -4 and solve for X. 6. 2A - B = 10X

A:

Q: Solve for x. 16 8 6. A. 3.33 C. 17 D. 18 14 B,

A:

Q: For Exercise, use A = -4 and solve for X. and B = -2 4 2X - B = A

A:

Q: Solve the following equation by making an appropriate substitution. 3x-2 - 17x-1 + 20 = 0

A: Given, 3x-2-17x-1+20=0

Q: Solve the equation for x. 20(2x - 8) = 440 A. 2 B. 5 C. 9 D. 15

A: Solve the equation

Q: Solve the following equation for l. A = 2πr + πrl. Explain each step.

A: A = 2πr + πrl. We transfer 2πr to the left.  Hence πrl = A - 2πr

Q: For Exercise, use A = and B = [6 -4 and solve for X. 4 9. –2. B - 4X = A

A:

Q: 2x + 3y = 51 6x + 3y = 87 %3D %3D

A: Given equations are: 2x+3y=51...............(1) 6x+3y=87...............(2) x=9(given)…

Q: For Exercise, solve the equation. 3 5 За + 4 5a – 1

A: Cross multiply

Q: b) X-10° R. T.

A:

Q: Solve the following equation by using Substitution: (4x – 3)2 – 6(4x – 3) + 5 = 0 Start by saying…

A:

Q: For Exercise, solve the equation. 5y – 3 – 2y + 1 = 0]

A: Add 4th root of (2y+1) with both sides.

Q: Given that y = 1.6−x,  write an equivalent equation in the form  y = bx, with  0 < b < 1   y =

A: Just note that a-m=1/am

Q: P. 40° R bg S.

A:

Q: For Exercise, find the real solutions to the equation.  x2e^x−e^x = 0

A: Consider the provided equation,

Q: HW. Similarly solve x=fl =47

A:

Q: Solve the following equations: |2r +3/-|x -2|=6x 2x +3

A:

Q: For Exercise, solve for the indicated variable. 3 -m' for m, m > 0

A: Given that, Q=34m3           ...(1)

Q: For Exercise, solve the equation. Vx + Vx + 2 = 3

A:

Q: For Exercise, solve the equation. 4v 10 = v + 5v – 25

A: