for k = 235, we have n(235) = 2^2 + 3^2 + 5^2 = 38. determine whether the function n(k) is an injective, surjective, or bijective function. n : N → N
for k = 235, we have n(235) = 2^2 + 3^2 + 5^2 = 38. determine whether the function n(k) is an injective, surjective, or bijective function. n : N → N
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 60E
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for k = 235, we have n(235) = 2^2 + 3^2 + 5^2 = 38. determine whether the function n(k) is an injective, surjective, or bijective function.
n : N → N
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