For nonempty sets A, B, and C, |A| <= |B| and |B| <= |C|, then |A| <= |C|.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter1: Fundamentals
Section1.7: Relations
Problem 6E: In Exercises 610, a relation R is defined on the set Z of all integers, In each case, prove that R...
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For nonempty sets A, B, and C, |A| <= |B| and |B| <= |C|, then |A| <= |C|. 

I know this is true because numerical equivalence is an equivalence relation. So do I prove this by showing an injection from A to C? 

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